Madonna to perform ‘Same Love’ with Macklemore and Ryan Lewis at Grammys

The Recording Academy has confirmed that Madonna is scheduled to appear at the 56th annual Grammys alongside Macklemore and Ryan Lewis. The trio will be performing the gay anthem “Same Love.”

Although no other details have been revealed, Madonna has been hyping the performance on Instagram.

“My lips are almost sealed!” she wrote, adding a photo of herself covered in a thin black veil. “I can’t say anything more. #itsasecret.”

“It’s official! I’m off my crutches and I’m looking for the perfect pair of heels to wear to the Grammys,” she added.

The dancing queen recently sustained minor injuries from all that onstage werk in heels.

Other Grammy performers include Miranda Lambert, Billie Joe Armstrong, Juicy J, Trombone Shorty, Jay-Z, Pharrell Williams and Kendrick Lamar.

The 56th annual Grammy Awards will be hosted by LL Cool J and will air live Sunday night from the Staples Center in Los Angeles.

Keep Reading

‘Monster’ butchers queer history to tell a tale of lesbian revenge

In rewriting Lizzie Borden’s story, Ryan Murphy’s show sensationalizes women’s violence
Josh Silver

‘Fruit Fly’ author Josh Silver has a sweet tooth—and the summer’s buzziest book

The English writer talks the duality of social media, how nursing helped his draft—and the cost of massive success

How ‘North of North’ is introducing Indigenous queer dramedy to a global stage

Actors Anna Lambe and Zorga Qaunaq on learning about forgiveness and queerness through their award-winning show
Barbara Hammer

Barbara Hammer’s endless influence

The lesbian filmmaker made a radical difference by making work that reflected her real life. A new documentary is cementing her legacy
Advertisement